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Renovation of floating-head heat exchangers

2018-06-20 View Original

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There is a floating-head heat exchanger that was originally used with medium-pressure steam at 1.0 MPa and 180 degrees to vaporize butane or propane. Due to shortages of steam, efforts were made to save energy; now it is planned to use steam at around 0.5 MPa and 130 degrees to vaporize butane or propane. The flow rate of butane or propane is required to be between 5 and 8 tons per hour, with the outlet temperature to be controlled between 55 and 80 degrees. How can this requirement be met through proper design? What is the flow rate required for steam condensate? I hope the experts here can help; thank you!
Reply #2 2018-06-20
This is a simple phase-change heat exchanger using water and propane, requiring approximately 4.2–4.5 tons/h of water
Reply #3 2018-06-20
I want the propane temperature to be between 55-80 degrees; please check the parameters carefully before giving me a response
Reply #4 2018-06-20
How is it calculated? It would be different if it were butane, right? A phase transition occurred
Reply #5 2018-06-20
It’s not from 55 to 80 degrees, but at room temperature; propane does not exist in a liquid state at room temperature. And how much water needs to be condensed for butane to go from room temperature to 50-80 degrees?
Reply #6 2018-06-20
As long as there is a phase change, it’s different; the amount of heat absorbed is different
Reply #7 2018-06-20
Could you explain the specific calculation method? Thank you!
Reply #8 2018-06-20
Water side: Check the enthalpy-temperature table to determine the heat transfer amount. Propane side: Calculate the enthalpy difference, using the formula heat released = heat absorbed. I used HTRI to make an approximate calculation, as I don’t have the property parameters for propane available

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