Seeking advice on heating cold water with one ton of steam.
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One ton of steam at 2.0 MPa and 210°C. Mix in together. In water at 10℃, it is required to raise the temperature to 85℃. How many tons of hot water can be obtained? It would be best to have a calculation formula.
Using the formula Q_absorbed = Q Released, where Q Released = the heat released when saturated steam turns into water at 85°C * steam flow rate = (2796.4 – 356.44) * 1 = 2439.96. Q_absorbed = the heat absorbed when water at 10°C turns into water at 85°C * water flow rate; thus, water flow rate = Q_absorbed / heat absorbed when water at 10°C turns into water at 85°C = 2439.96 / 313.83 = 7.77 tons. The enthalpy values for steam and water can be found online; I simply made an approximate estimate by referring to tables!
Generally, one ton of steam can heat about 7 tons of water!
Q_release = 1000*1890 + 1000*4.3*(210-85) = 2,427,500 kJ/h. The amount of water heated == 2,427,500 kJ/h / 4.2 / (85-10) = 7,706 kg/h. Plus, 1 ton of steam is required to produce 8.7 tons of water
1000*(H1-H2)=X*(85-10)*4.187. H1 is the enthalpy of steam at 2.0 MPa and 210°C, in kJ/kg; H2 is the enthalpy of water at 85°C, in kJ/kg. X represents the amount of water to be heated, in kg. X+1000 represents the amount of hot water produced, in kg. If simulation is possible, it can be done using software to obtain the result
Just perform a heat balance and a material balance; it’s not difficult.