【Daily Question】Theoretical Foundation 2019.7.18
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Multiple-choice question: Water flows in a circular tube with a diameter of Ф38×2.5 mm at a flow velocity of 0.1 m/s. Given that the viscosity of water is 1 mPa·s, what is the flow regime? A. Laminar flow B. Turbulent flow C. It could be either laminar or turbulent flow D. Neither laminar nor turbulent flow. Answer: C. Hint: The answer can be seen upon response
C. It can be laminar or turbulent
The inner diameter of the pipe is 0.033, the density is 1000, and the flow velocity is 0.1. The viscosity of water at 20°C is 0.001; therefore, 0.033*1000*0.1/0.001 = 3300. This value falls between 2000 and 4000, so the flow could be either laminar or turbulent
C. It can be laminar or turbulent
Water flows in a circular tube with dimensions of Ф38×2.5 mm at a flow velocity of 0.1 m/s. Given that the viscosity of water is 1 mPa·s, its flow pattern is (C. It could be either laminar or turbulent)