I implore the experts!
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Two identical media at different temperatures: one is in a mixing container at 74 degrees with a mass of 3500 KG, while the other will be added in an amount of 1500 KG at 65 degrees. What will be the temperature after mixing? Is there a formula for this? I implore the experts!
You need to know the specific heat values of these two substances between 65 degrees and 74 degrees
He said it’s the same medium. :P
This post was last edited by Lantian on 2017-3-1 at 13:08. According to Q=cm△t, the total amount of heat remains constant; the heat absorbed at lower temperatures equals the heat released at higher temperatures, without taking into account any heat generated or lost due to other factors. C*3500*（74-t）=C*1500*(t-65); the calculation yields t=71.3 degrees
This is how it is under normal circumstances. If a precise calculation is to be done, it is indeed necessary to know the specific heat capacity. Since specific heat capacity is calculated through integration, different materials have different heat capacities at different temperatures.
To calculate this final temperature, several conditions must be set. 1. If the specific heat of the medium is the same at 65–74 degrees ； 2. Ignoring heat dissipation of the medium ； 3. The heat transfer of the medium by the equipment itself (including materials in contact with the medium such as the container walls and stirrers) is not taken into account. Under ideal conditions, the temperature of the medium should be 73.1 degrees. In actual conditions, it should be higher than this temperature.
3500*(74-T)=1500(T-65); solving this equation gives T=71.3. Calculation complete; P