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The problem of work performance in reciprocating compressors

2018-05-07View Original

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I would like to ask: what is the difference between cranking a reciprocating compressor at 2 MPa and 0.5 MPa with the return valves fully open, in terms of power generation? Personally, I think the difference is minimal. Can the work done by the piston in such cases be expressed using the formula W = ΔP (pressure difference) * S (area) * L (stroke)? Is the increase in pressure, which leads to an increase in gas density, the fundamental reason for the increase in work done? (Waiting online: lol)
Reply #22018-05-08
An increase in pressure actually means an increase in the amount of substance. It’s like the energy required to lift an object of 1 KG vs. one of 2 KG is different.

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