Note: Case 2017, Question 4 in the afternoon
Thread Content
How is this problem solved? Thank you
4[Analysis]: The total mass transfer resistance for A is 1/Kya = 1/kya + m/kxa = 1/0.025 + 0.1/0.02 = 45. When the gas flow rate is doubled, the new total resistance becomes (1/Kya’) = 1/0.025 * 2^0.6 + 0.1/0.02 = 31.4. Thus, the percentage decrease in total resistance is: (45 – 31.4)/45 * 100% = 30.2%.
Where can I find this formula?
The chapter on Principles of Chemical Engineering from Tianjin University (3rd edition, Volume 2, edited by Chai Chengjing et al.) covers that content.