How to determine if a pump is suitable for air shipping
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If it seems that some pumps in the workshop can still transfer fluids without it, how can one determine this precisely? Testing is not possible during operation; only when everything is certain can testing be carried out. What should be done in such a situation?
I didn’t understand your question. When the pump runs idle, noise, vibration, and current levels all increase; in the case of a canned motor pump, this can cause the pump to shut down. It’s easy to judge.
The function of a pump is to add energy to a fluid medium. There is pressure at both the inlet and outlet of the pump; if you believe that the pressure at the pump’s inlet is sufficient to deliver the medium to the target device, you can omit the pump.
I don’t see how your question is related to the description; by listening to the sound when the pump is running idle, it’s possible to get a rough idea
I don’t understand what you mean; the title does not match the content of the text.
This post was last edited by eidl*ang on 2017-1-12 at 11:51. It seems I understand now. When people talk about \"pumping by air transport,\" it refers to the pump operating at low load, performing less work and thus operating with low efficiency. If the medium can meet the transportation requirements, from an energy-saving perspective, it would be advisable to shut down this pump, right? It’s simple – just calculate the potential energy! Subtract the two numbers.
The function of a pump is to add energy to a fluid medium. There is pressure at both the inlet and outlet of the pump
It seems that there is no flow rate indicator available for making such judgments. There is another reliable method: when there is no flow or the flow rate at the pump outlet is too low, the pump body heats up, with a temperature significantly higher than that of the pipes at the pump inlet; even the pipes near the pump inlet also heat up, with a temperature higher than that of the pipes further upstream.
It’s what was meant on the sixth floor; it’s my fault for not explaining it clearly
The method has been mentioned above; I hope it can help you.