Regarding the actual lifting height of the pump
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I have a question that has been bothering me for a long time. Suppose a slurry pump is used to pump clean water, with only one valve at the outlet. The pipeline is extremely long, and pipeline resistance must be taken into account. When the pump is started, the clean water will rise to a certain height and then come to rest, say at 50 meters. If the valve is then closed, will the height of the water change? If we go by the principle that as flow rate decreases, head increases, then the height increases ； Taking pipe resistance into account, the increased head (energy) loss is incurred at the valve, with the height remaining unchanged. What exactly is the situation? In the second case, closing the valve can only regulate the flow rate; it has no other effect. But when we use water in our daily lives, how can we explain the phenomenon where, by squeezing the pipe, the water flows further? Also, I would like to ask whether this principle of \"reduced flow rate and increased head pressure\" applies to all pumps?
There is one fundamental assumption when squeezing a water pipe: the flow rate of water remains constant, whether it’s tap water or water pumped by a pump. With a constant flow rate, squeezing the front end of the pipe reduces the cross-sectional area through which the water flows. Under these conditions, as the area decreases, the speed of the water increases, resulting in a greater range for the water jet.
There is one fundamental assumption when squeezing a water pipe: the flow rate of water remains constant, whether it’s tap water or water pumped by a pump. With a constant flow rate, squeezing the front end of the pipe reduces the cross-sectional area through which the water flows. Under these conditions, as the area decreases, the speed of the water increases, resulting in a greater range for the water jet.
I’m sorry; I was trying to delete my duplicate reply and accidentally deleted your post. I’m truly apologetic.