Calculation of dosage for rotary spray semi-dry desulfurization

This post was last edited by wenlong1017 on 2015-10-8 at 13:34. What reference books are you using? The calculations in them seem correct to me. You can figure it out by working backwards from the reference book to determine the calcium-sulfur ratio. 110000*8580/1000000 calculates to 1415.7 kg/h

You’ve miscalculated; 110000*8580/1000000 = 943.8 kg/h. Using the approach you described, I’ve worked backwards to determine that the calcium-sulfur ratio is 14

Let’s see if these people have more opinions. @yjqin1 @jacques0920 @WiseAndClear @IceQueen @hjhjxnyt @ylb913 @EvilIncarnate

Have they used rotary spray desulfurization?

I don’t know; maybe someone has used it, maybe they have seen it, or maybe there have been studies on it

Does going to the other person’s profile and sending them a message consume wealth points?

I don’t know. It might be worth giving it a try

This post was last edited by arpcd on 2015-10-10 at 22:53. The original poster is really confused – you only provide your own calculation process without showing how it’s done in the book. Wouldn’t it be clearer if you just posted a screenshot? Your calculation is unrelated to the desulfurization process used; the calculations for the desulfurizing agent are the same in all cases. If we are to talk about right or wrong, the biggest issues are likely to lie in the amount of flue gas and the SO2 concentration. The principle of calculation is that the flue gas volume and SO2 concentration must be matched. By \"correspondence,\" it is meant that if the flue gas volume is the volumetric flow rate under operating conditions, then the SO2 concentration must also be the concentration under those same operating conditions (on a wet basis, with the actual oxygen level, and under the prevailing operating conditions). If 110,000 m3/h refers to the value under operating conditions, then 8,580 mg/m3 should also represent the concentration under those same conditions. The \"m3\" in 8,580 mg/m3 must correspond to the \"m3\" in 110,000 m3/h, so that the values can be multiplied directly! If these two M3 values are not the same at all, you can’t simply multiply them together; an conversion is necessary! ! Generally speaking, almost all of China’s emission standards for air pollutants (applicable to all industries) specify that pollutant concentrations are to be based on dry flue gas at 273 K (i.e., 0°C) and 101325 Pa (standard atmospheric pressure). In the case of boiler flue gas, it is also necessary to adjust these values using standard oxygen levels; for coal-fired flue gas, this standard oxygen level is 6%. Therefore, if the flue gas comes from a coal-fired boiler and the original SO2 concentration is 8580 mg/m3, then, unless otherwise specified, this concentration refers to 8580 mg/m3 under standard conditions, on a dry basis, with standard oxygen levels. According to common practice in the engineering field, this value should be expressed as 8580 mg/Nm3; however, Nm3 is not a unit recognized by ISO, but you can understand it in that way. In other words, the value of 8580 mg/m3 is the data provided by the CEMS analyzer; the unit ‘m3’ refers to standard conditions, on a dry basis, with standard oxygen levels. Therefore, you cannot simply multiply by 110000. . . At this point, for your 110,000 m3/h value, you still need to deduct the water content (converting from wet basis to dry basis), make corrections for temperature and pressure (the original flue gas temperature is 160°C, which needs to be converted to 0°C under standard conditions), convert it to Nm3, and then further convert it to Nm3 at standard oxygen conditions, before multiplying by 8580. . The original poster should take a close look at how these details are described in the book; moreover, what kind of book is it? Is it a book or a design specification? Or technical guidelines? ? Whether it’s desulfurization or denitration, these basic principles remain the same. . . . Most of the current books and materials on desulfurization are copied; if the original version is incorrect, all the errors will be copied along as well. Hehe. . . Personally, I think it’s a printing error; the consumption rate of 13.12 t/h should actually be 1.312. It’s a shame that the original poster didn’t even include any images – after all, \"no pictures, no truth\". . . .

Since the company’s computers don’t have messaging apps and it’s not convenient to upload photos, I referred to the book \"Engineering Technologies and Equipment for Flue Gas Desulfurization and Denitrification.\" The values regarding the volume of flue gas given in that book are definitely incorrect; the example in the book relates to a coal-fired boiler with a capacity of 200 MW, and the value for the flue gas volume is off by one zero. The value I provided for the flue gas volume refers to the operating conditions, and the SO2 concentration also corresponds to those operating conditions, so the units are consistent. If the flue gas volume is 1,100,000 m3/h, my calculated result is close to that in the book. Reference books can only be used as a guide – some of the data in them need to be verified carefully. Thank you again for your response.

Hello, I have a question: the flue gas volume you mentioned refers to the inlet conditions, right? So how did you calculate the flue gas volume under the outlet conditions? Thank you so much!