Converting volume percentage of liquefied gas to mass percentage
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In our laboratory, when analyzing liquefied gas, we obtain the volume fractions of various components. Is the mass of each component equal to its volume fraction multiplied by its specific gravity? (How to calculate the mass fraction of each component given the volume fraction?) I hope the teachers can provide some guidance! Thank you!
I hadn’t thought of that; it’s sufficient to simply use the area normalization method
I just want to figure out how much propylene, propane, and things like that are in the liquefied gas It is easy to operate the gas separation device.
The volume ratio is the same as the molar ratio, and the mass ratio is then calculated from the amounts of substance of the components
After sampling, there is a volume ratio; just treat the volume ratio as a molar ratio for the calculations
M=30*0.00014+42*0.34106+44*0.09018+57*0.55514+72*0.01344=50.907; therefore, the mass fraction of propylene = 42*0.34106/50.907 = 0.281
See if you can understand it – it’s just about calculating the average molecular weight and then comparing it to that of propylene
Wutong gave directly the formula; I’ll explain the principle here, but this is knowledge from junior high school. It seems you don’t recognize it when it’s presented in a different form {:3_62:}. Since mass = volume * density, and weight is proportional to mass, multiplying the ratio of volumes by the ratio of densities gives the ratio of masses, which is also the ratio of weights.
0.281 multiplied by the volume of the feed gas gives the mass of propylene.