Problems with the power source of the reactor reflux setting
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In the reactor designed by the design institute, the pipe mouth is connected to the condenser, and then the U-shaped pipe is liquid-sealed and returned to the reactor. The two pipe mouths should have the same pressure in the reactor. What is the power source for the gas phase in the reactor to be condensed and then returned to the reactor? Thank you!
Is the liquid level difference causing backflow? Let’s take a picture.
I found a picture on the Internet. The design of our design institute is similar, but it seems that there is no VT and VA exhaust. It is easy to understand that there is an exhaust line. The pressure at the exhaust point is lower than the inlet, and it condenses through the condenser (the U-shaped meniscus seal ensures that it does not pass through here).； If it is not drained, the pressure in the reactor to decondensate will be the same as the pressure coming back from the U-shaped bend. How to ensure that the condensation line is smooth?
The two pipes VT and VA must not be normally open, but only open when needed, so there is no problem in the reaction gas phase being condensed and self-pressurized by the liquid level difference to return to the reactor.
The liquid in the reactor evaporates, the pressure rises, and the gas phase enters the condenser. After cooling, it turns into liquid and enters the U-shaped bend. As the liquid increases, a pressure difference is formed and enters the reactor. It seems that the original poster is not familiar with the workshop.
A typical open system, and the boiling point of the solvent is lower than the reaction temperature, cooling reflux is set up to avoid losses caused by massive evaporation of the solvent and an increase in the cumulative concentration of reactants.
The pressure is the same if there is no liquid in the tube, but it is different if there is liquid.
How high is the U-shaped bend?