Seeking advice on steam temperature and pressure reduction
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How many kg of water need to be added to reduce 1 kg of steam at 1.0 Mpa (gauge pressure) to steam at 0.3 Mpa (gauge pressure)? Please ask friends to help with the calculation. Also, is there any software available for such calculations? If so, could a friend please send it to me? My email address is 287519887@qq.com. Thank you in advance.
0.017 kg of water at 25°C is required.
May I ask, how is it calculated?
Look up the enthalpy value H1 of steam at 1 kg and 1.0 Mpa (gauge pressure), as well as the enthalpy value H2 of steam at 0.3 Mpa (gauge pressure). Also find the enthalpy value H3 of water. Based on the law of conservation of energy, we have 1*(H1-H2) = (H2-H3)*x; by solving this equation, we can determine the value of x
The enthalpy of steam at 1.0 MPa is 2782.5; the enthalpy of water at 26 degrees is 109.3. The enthalpy of steam at 0.3 MPa is 2728.5. Therefore, 2782.5 + x*109.3 = (x+1)*2728.5, which gives x = 0.021
The original poster can use any simulation software to carry out the calculations, which is very convenient and fast. A control valve, a mixture, and a controller.
Due to a lack of data, the building owner needs to provide the steam temperature.
I learned it! @wsy417 :D
It needs to be calculated, as different manufacturers use different type of temperature-reduction nozzles, and there are variations in their design