Interesting calculations of membranes, let’s get active and take a look
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Assume that during the membrane flux measurement experiment, 10 ml of permeate was taken each time, and the effective area of the membrane was 895.35 square centimeters. The measurement data showed that the measurement time (min) of each time was: 2, 4, 8, 16, 32, 64 ； ask: What is the average permeate flux of the membrane measured this time? (The calculation process and results must be included) (The effective area of the membrane and the measurement time of each measurement have been simplified. I hope that friends who can make it can reply and send me a text message to tell me quietly, haha! ! ! ) This post was last edited by bolinuser on 2008-1-10 20:50 ]
This question is very simple, I hope everyone will actively participate! ! ! Don't let this post go down like this. Please participate if you know how to do it. This post was last edited by bolinuser on 2008-1-12 21:20 ]
0.65966L/m2.H Right or not :)
I don’t have the rights to the rating area at the moment, so I can’t rate everyone, but there are some minor mistakes.
Recently, the company is working on a project with a membrane company, but nothing is confirmed yet.
The test conditions are not provided completely. If you want to calculate, you should provide complete ones.
P=F/A/T Does the permeate refer to the total volume on the permeate side? Another question is, how much is the processing capacity? If the same membrane can be completely processed in five minutes and 10ml of liquid is obtained on the permeate side, the subsequent time is meaningless for calculation.
Each measurement time is 2, 4, 8, 16, 32, 64? What does LZ mean? Normally, the flux is measured by sampling a fixed area at a certain time to measure the volume of the permeated sample, while the opposite is true for LZ. . . And do you think this time is exaggerated? It takes 16 minutes to take 10ml for the fourth time? The penetration flux formula J=V/(At), it goes without saying what the symbols in the formula mean.