HCBBS Forum (English)
Submit Chemical Projects / Find Solutions
Amplify Your Requirements on a Broader Chemical Platform *Engineering · Technology · Equipment · Solutions*
Submit Request

Condition of slot voltage when increasing current

2008-01-29View Original

Thread Content

This post was last edited by sunjl1981 on 2013-1-6 at 23:38. The polarization cells in our factory are of the forced-circulation, low electric density type manufactured by Beihua Machinery. I would like to ask several questions to the experts here: 1. Why, after filling the electrolyzer with liquid and raising its temperature, and then increasing the current (our electrolyzers have 100 cells, with an effective area of 2.7 square meters, and no polarization facilities), does the total load vary so greatly as the current increases, with the cell voltage ranging from 1 to 4 KA? At 1KA it is 193V, at 1.5KA it is 212V, at 2KA it is 234V, at 2.5KA it is 253V, and at 3KA it is 270V. Of course, a lower slot temperature plays a role when the current increases, but once the current rises above 6KA, the slot voltage increases by around 10–13V per KA. I just want to ask why, when the current starts to increase, the voltage drop per slot increases by such a large amount as the current rises Is it because charging the galvanic cell begins as soon as the current is increased, that the cell voltage quickly reaches the theoretical decomposition voltage? 2. I believe that when increasing the current, as long as there is current flowing in the circuit, the slot voltage should be greater than the theoretical breakdown voltage. Because an electrolyzer is a primary cell when no power is supplied to it, and power must be applied to it only if the voltage applied is greater than its electromotive force. However, observations made while increasing the current show something different; in fact, the voltage is 193V at 1KA, 212V at 1.5KA, 234V at 2KA, 253V at 2.5KA, and 270V at 3KA. Based on my understanding, at 1KA the total voltage across the battery cells should be at least the theoretical decomposition voltage multiplied by the number of cells: 2.17*100 = 217V. I’m very confused about this and hope that the teachers can help me understand it. First, tell me if my understanding is correct? ? 3. I would like to ask the teachers whether the cell back electromotive force and the cell galvanic effect are the same thing? # , , &
Reply #22008-01-29
As can be seen from what was mentioned above, you don’t yet have a good understanding of the concept of theoretical breakdown voltage
Reply #32008-01-29
Since this teacher can see that I don’t understand, why can’t they explain it to me? Is it really that conservative?

Submit a Project

**Looking for Chemical Technology, Equipment & Solutions?** No Registration Required Broader Platform Exposure | Global Chemical Service Provider Connections

Submit Request — Free Consultation

Disclaimer

This is an automated machine translation of the original thread. Some technical terms may have inaccuracies; the original text shall prevail. Click "View Original" at the top right to access the source page, which supports IP-based automatic real-time language translation. Please watch out for contact details and sales inducements to prevent fraud. All content and translations are for reference only, representing solely the poster's personal views. For enquiries, email service@hcbbs.com.