If the mass percentage of alcohol is 88%, what is the corresponding volume percentage?
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Who has any information on this topic? Could you please provide it? Thank you! ! ! !
If we use the density of pure alcohol, which is 0.8 g/cm3, we can calculate the result by setting up a linear equation: 0.88/（0.88+0.12*0.8）=90.0163%.
It’s not the algorithm upstairs; there are charts available for reference. The actual concentration is just under 92%.
As a rough estimate, without taking into account the solubility of ethanol, the formula should be 0.88 / (density of alcohol at this concentration) / ((0.88 / density of alcohol at this concentration) + 0.12). The density of alcohol with a concentration of 0.88 is approximately 0.7; by plugging this value in, the mass concentration comes out to be around 91.3%
The density is around 0.7……I’m not sure where this value comes from. At 20 degrees, the volume fraction should actually be 91.8%; this can be found in tables, or it can be calculated as well, but it’s necessary to know the exact density first
Alcohol with a mass fraction of 88% corresponds to a volume percentage of 91.8% (v/v)
Personal opinion: The specific calculation process should be as follows: 1. First, determine the specific volume Vm of an 88% (wt%) alcohol solution, which is given by Vm = X1V1 + X2V2, where v1 and v2 are the specific volumes of alcohol and water under these conditions, in cm3/kg; these values can be obtained from tables. X1 = 0.88 and X2 = 0.12 represent the mass fractions of alcohol and water, respectively. 2. Volume fraction v% = x1·v1/vm. Last edited by zhongshan2046 on 2008-8-14 17:31.]
Does anyone have a chart showing the volume percentage and mass percentage of that alcohol solution at various temperatures? Share it! Thank you……