I have a question about a practice exam
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For a gas at a temperature of 30 degrees and a pressure of 0.2 MPa, with a volumetric flow rate of 50 m3/h (under standard conditions), what is its molar flow rate? A 4.41kmol/h B 2.47kmol/h C 3.97kmol/h D 2.23kmol/h
50/22.4=2.23
It’s strange that the answer is C. This question comes from *Revised Tutorial for the Professional Examination of the Certified Chemical Engineering Engineer Qualification Exam (2nd Edition)*, the book with a purple cover; it’s question 4 on page 487
Shouldn’t it be PV=nRT? 22.4 is used for standard conditions, right?
V/N=RT/P; Molar flow rate = Volume flow rate / (V/N) = 3.968
I still don’t understand; the 50 in parentheses refers to standard conditions, right?
The pressure and temperature have changed; it’s not under standard conditions. The formula is V=22.4*n*((273+t)/273)*(101.33/p). I’m trying to find the value of n; I hope this helps you
Ugh, this question is poorly formulated; the parentheses indicate standard conditions, and it should be understood that this 50 refers to the volumetric flow rate under standard conditions. In fact, it can be calculated without using standard conditions. .