Note: Chemical Processing 2017 case, 10 PM
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10. There is an irreversible first-order reaction carried out in an ideal batch reactor at a reaction temperature of 120°C. The reaction rate constant is 0.015 min-1, the initial concentration of reactant A is 4 mol/L. Production occurs continuously 24 hours a day, with a product yield of 5000 kg/day. The molecular weight of the product is 278. The time required for loading and heating per batch is 62 minutes, while cooling, unloading, and cleaning take 37 minutes. The conversion rate is 98%, and the loading factor is 0.8. What is the volume of this reactor in cubic meters? (A)1.5 (B)2.0 (C)2.5 (D)3.0 How can the molar flow rate of reactant A be determined from the molar flow rate of the product? ? The molar ratio of the product to reactant A is not necessarily 1:1
Isn’t there a conversion rate? The conversion rate = moles of product / moles of reactant
This post was last edited by dnl3027 on 2018-8-9 at 10:39. The answer I came up with is similar to option A; I’m not sure if it’s correct FA0=5000/278/0.98/24/60=0.0127 kmol/min; v0=FA0/CA0=0.0127*1000/4=3.186 L/min; t=1/k*ln(1/(1-xA))=260.8 minutes; tt=260.8+62+37=359.8 minutes; V=v0*tt=1146.3 L; VR=V/φ=1432 L≈1.5 m3
Conversion rate = moles of reactant that have reacted / total moles of reactant. However, the number of moles of reactant that have reacted is not necessarily equal to the number of moles of product
It is possible to calculate such an answer, but the reactants and products are not necessarily in a 1:1 ratio ?