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Question 9 in the afternoon session of the 2017 Chemistry exam

2018-10-15View Original

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A certain reaction employs a series-parallel reactor arrangement as shown in the figure below: FA → V1=8m3 → V2=10m3; FB→V3=3m3→V4=? At standard conditions, the volumetric flow rate FA in branch A is 2/3 of the total feed flow rate F, with the reactor operating conditions being the same for both branches. If the conversion rates of the two lines are the same, what is the volume (in m3) of Reactor 4? (A)5 (B)10 (C)4 (D)6 Please help me solve this, experts!
Reply #22018-10-15
Tell me how to do it? I have no idea how to approach this problem
Reply #32018-10-19
At the moment, we can only conclude that it’s 6 by assuming the conversion rates are the same, and thus the time spent on the site is also the same; I still don’t quite understand this

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