Let’s talk about this year’s Juhua exam
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After taking the case study exam, I felt like I was in trouble this year – my score was right on the passing mark. Ugh, I really didn’t prepare enough
Proposition experts are getting more and more overconfident: they create a few difficult questions, some with heavy calculation requirements, select some real exam questions, and include one or two for which no answer can be found, all in order to trick the candidates
The pipeline calculation problem in the case study session in the afternoon really shocked me; it took me 30 minutes to solve it, and it’s not worth those two points at all
I’ve tried calculating everything but can’t find an answer; I’m starting to doubt life itself:L
The questions are becoming more and more unconventional; if you can’t pass them, then there’s no point in taking the exam. The Certified Public Accountant exam is losing its value increasingly
1. I remember the case from the afternoon; it was probably question 3, a absorption-related problem. Given the molar fraction in the gas phase, the absorption rate, the absorption coefficient m, and the liquid-to-gas ratio used in the operation, it’s possible to calculate Nog. Additionally, with a plate efficiency of 27%, the actual number of theoretical plates required can be determined. But I’ve tried hard yet still can’t figure it out 2. For question 4, in the case of non-isenthalpic drying, the relationships between I2, t2, and H2 for the air are determined based on the exit temperature. The enthalpy values of the material before and after drying are found using the equation L(I1-I2) = G(I2’-I1’); after going through various calculations, the answer is obtained, but no options are provided
I want to show off a bit: the second question in the afternoon is about desorption. Use S for the calculations, not A. The number of theoretical plates is NT; divide that by the plate efficiency, and you’ll get the answer! For question four, first calculate the air volume using isenthalpic methods; then use (heat loss + heat required to raise the temperature of the dry material) / air enthalpy to determine the additional amount of air needed. Adding these two values gives the answer!
Impressive, I couldn’t solve question 4 either; I was completely confused at that time
Let’s discuss Question 4 again. My idea is: 1. The premise is based on non-ideal drying, so I2 is not equal to I1； 2. The amount of water removed through drying is calculated to be 19 = L (H2 – H1). For the heat balance, we have L (I1 – I2) = G (I2’ – I1’) + QL_loss. There are formulas for I2 and H2, and it is necessary to solve a system of equations in order to determine L. 3. Friend, you’ve calculated how much extra air there is, but I didn’t think of that at all. I maybe didn’t consider all the given conditions properly, or I didn’t understand the material well, haha ……
For question 4, you can refer to the association’s* question set
I can’t do Case 1 either; I don’t know how to solve it and I get panicked right away. .