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Calculations for coiled tubes using heat transfer oil for heating asphalt tanks

2008-10-16View Original

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It is difficult to find calculations regarding the heating of asphalt tanks using heat transfer oil. I was wondering if anyone has any useful reference books? Now, construct an asphalt tank with a volume of 1,000 cubic meters, to be heated using heat transfer oil.
Reply #22008-10-16
I’ve also looked up information on this topic. Is what you have a solid form of storage, which is then heated to release it when in use?
Reply #32009-01-08
Did you manage to figure it out in the end? Do you know how to calculate it?
Reply #42009-01-09
Oil tank heaters: The heat required for heating an oil tank is given by the formula: Q_add = q_oil – q_loss = M•C(t1–t2)/b + KF(ty–t0)/s. Here, Q_add represents the heat required to heat the asphalt, in kj/h; q_oil is the heat needed to raise the temperature of the oil, also in kj/h; q_loss is the heat lost by the tank during the heating process, in kj/h. M denotes the mass of the oil being heated, in kg; t1 is the final temperature after heating, in °C; t2 is the initial temperature, in °C. C is the average specific heat capacity of the oil at temperatures t1 and t2, in kj/kg•°C. K is the heat transfer coefficient from the tank walls to the air, in kj/m2•h•°C. s is the time required for heating, in hours. F represents the surface area of the storage tank, in m2. Ty is the average temperature of the oil, calculated as ty = (t0 + t2)/2, where t0 is the ambient temperature, in °C. The heat required for insulating the oil tank is calculated using the formula: Q_insulation = M•C•Δt. Here, Q_insulation is the heat needed for insulation, in kj/h; M is the mass of the oil that needs to be insulated, in kg; C is the specific heat capacity of the oil, in kj/kg•°C; Δt is the rate of temperature drop, in °C/h. When the external temperature is between 12–15°C, the rate of temperature drop should not exceed 2°C/h. Calculation of the heating area for tubular heaters in oil tanks. Heating area F (m²): Where Q is the total heat required to heat the oil per unit of time, in W; K is the overall heat transfer coefficient, in W/m²·°C; t1 is the temperature of the heat source at the inlet to the heater, in °C; t2 is the temperature of the heat source at the outlet from the heater, in °C; ty is the average temperature of the oil inside the tank during heating, in °C – for ty, the arithmetic mean is used when >2, while the logarithmic mean is used otherwise; tys is the initial temperature of the oil during heating, in °C; tyz is the final temperature of the oil after heating, in °C; ti is the temperature of the medium surrounding the oil tank ℃
Reply #52009-02-09
The reply upstairs was quite detailed; thank you very much. It’s a pity that the formula for calculating the heating area at the end doesn’t seem to be shown
Reply #62009-02-09
It should be an image! It has already been notified!
Reply #72009-02-10
First, it is necessary to find the basic data for the heat transfer oil, namely the enthalpy values at various temperatures. The heat release can be calculated. The rest is basically the same as steam
Reply #82009-03-17
Boss, please send over the formula at the back, or maybe that kind person can provide it – I really need this formula urgently. We use hot water for heating, and I’m not sure whether this formula applies in that case
Reply #92009-05-18
The calculation formula F=Q/K is from the book \"Oil and Gas Storage and Loading/Unloading Systems\", edited by Xu Yupeng and Lan Baikang
Reply #102010-01-27
Yes, I’ve never done calculations of this kind before; I wonder if anyone can provide an example of such a calculation
Reply #112010-03-04
I exactly need information in this area; thanks to the original poster

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