A question about production
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How many tons of 31% hydrochloric acid are needed to produce one ton of 99% HCL gas? How to calculate it? :lol
! ! Junior high school chemistry? Or am I too naive? 1 (ton) × 99% ÷ 31% = 3.3 (ton)
When the loss is zero, about 3.2 tons of HCL aqueous solution is needed. This post was last edited by Albertlu on 2009-2-2 15:44 ]
1 (ton) × 99% ÷ 31% = 3.3 (ton) and then divided by the conversion rate
This is a test question during the desorption process of hydrochloric acid. 31% of the hydrochloric acid enters the desorption tower from the top of the tower. The tower kettle is heated by steam, and 99% of HCL gas comes out of the top of the tower. It won't be that simple. It should be around 8. But I don't know how to calculate it?
1 (ton) × 99% ÷ 31% = 3.3 (ton). In actual production control, it can be around 2.8 tons.
You also have to consider the concentration of the remaining liquid in the tower still. It should be easy to calculate based on the material balance.
With conventional desorption, the HCL solution can only be desorbed to 18-20%. At this time, the solution forms an azeotrope and can no longer desorb HCL gas. Deep desorption can break the azeotropic point of the solution, and finally desorb to about 0.7%. The 0.7% HCL solution is treated with waste acid. Current industrial production cannot achieve 100% desorption. Determine the desorption method you choose. This problem is very simple. The calculations on the above floors are all correct.
Thank you to the brothers and sisters upstairs. It’s not deep desorption, it’s normal. The concentration of dilute acid in the tower tank is about 21%. Can you tell me specifically how to calculate it? ? Thank you!
I think you did it the other way around. It should be HCl gas producing hydrochloric acid.