Is it possible to avoid using a heat exchanger in this situation?
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Two fluids at different temperatures exchange heat with each other before entering the same container. I would like to ask if it is possible to eliminate this heat exchanger? Let these two types of flow mix directly before entering the container, or enter the container directly. Please share your opinions.
When two fluids at different temperatures exchange heat with each other and then enter the same container, if there is no chemical reaction involved and it is merely a physical mixing process, these two fluids can be mixed directly before entering the container; or the container itself can function as a mixed-type heat exchanger. If a chemical reaction occurs, and such reaction is temperature-dependent, then this heat exchanger cannot be omitted.
There is no chemical reaction between the two fluids; it is a pure physical mixture
OP, could you please specify the materials and processes involved? Can we try to understand the intentions of the original designer? Simply rejecting the original design can sometimes lead to unexpected consequences. Be careful
The pure physical mixing of two fluids should generally allow for direct mixing. If the temperature difference is too large, causing one fluid to vaporize the other or to undergo other physical changes, measures should be taken to prevent phenomena such as \"water hammer\" from occurring.
If the mixing enthalpy is too high, a heat exchanger is necessary. For example: issues such as mixing 97% sulfuric acid with 104.5% fuming sulfuric acid
"Two fluids at different temperatures exchange heat with each other before being placed in the same container. This design approach is usually adopted due to the properties of the substances at those temperatures (such as changes in mixing enthalpy, corrosion characteristics, etc.); otherwise, such a design would not be used.