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Pump load calculation

2009-02-10View Original

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Excuse me, I want to use a pump to transport light hydrocarbons, with a flow rate of 2.4 t/h and an outlet pressure of 1.8 MPa. Will the pump listed below work for this purpose? Can the load be met? How is it determined? Serial number, device name, process code, device model, device category, time of commissioning, medium performance parameters, motor flow rate (m3/h), head (m), outlet pressure (MPa), outlet temperature (℃), rotational speed (rpm), manufacturer, model, voltage (V), current (A), shaft power (KW). Manufacturer: 1 CAM44/6 pump, 200310; Light hydrocarbons. 20375, 3.0402925, N80rm-238011853. 2 CAM44/6 pump, 200310; Light hydrocarbons. 20375, 3.0402925, N80rm-238011853
Reply #22009-02-10
If the density is taken as 600 kg/m3 and the pump efficiency is 0.78, the shaft power is 16 KW; using a 53 KW motor would be a waste!
Reply #32009-02-10
Thank you for the help. . . May I ask, if I choose based on flow rate and head, will the pumps listed in the table be sufficient? Our company is now using the pump listed in the table; we can’t replace it as we need to increase production. Let’s see if this pump will be sufficient.
Reply #42009-02-10
Formula for calculating pump shaft power: P=ρgQH/1000η, with the unit in kw. Where η is % ; g gravitational acceleration ; Q is in m3/s ; H is m ; ρ is in kg/m3
Reply #52009-02-10
I’m not sure how much more flow you need; adding another 20 m3 should be no problem.
Reply #62009-02-11
"I want to use a pump to transport light hydrocarbons, with a flow rate of 2.4 t/h and an outlet pressure of 1.8 MPa. Will the pump listed below work? Can the load be met? How was it determined that this parameter is not suitable for the pump provided? Firstly, the type of pump is not clear. If it is a centrifugal pump, there is also the issue of the performance curve; the flow rate used is less than 30% of the pump’s rated flow rate. Even if it can function, this leads to significant damage to the pump, so its use over a long period is not recommended.
Reply #72009-02-18
The motor power is calculated using the following formula: N_motor = K × N_pumpshaft_power / η_motor, where η_motor represents the transmission efficiency of the motor. K is a factor representing the margin for selecting the motor’s rated power; a value of 1.3 is sufficient in your case. The shaft power of a pump is calculated using the following formula: Pump shaft power = Q×H×ρ/(367×η_pump efficiency). The above are all calculation formulas for centrifugal pumps.
Reply #82009-02-19
There are two aspects to determine whether it is sufficient: one is flow rate and the other is head. The original specification for this pump had excessively high flow rates and heads, which means its power requirement is much higher than necessary; as a result, its efficiency is very low – in other words, it’s like using a large engine to drive a small vehicle. Currently, the modification should be calculated based on the actual required flow rate and head, to determine whether the shaft power can meet the demands.

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