How to calculate the vacuum pumping capacity of a concentrator
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How is the vacuum pumping capacity calculated for a concentrator with an evaporation rate of 1000 L/h? The vacuum effect is simply used to maintain a vacuum level of -0.09. The evaporated solution is not removed by vacuum. Last edited by brainandrain on 2009-2-14 at 13:48.]
The evaporated solution is not removed by a vacuum pump or unit; evaporation systems are equipped with condensers, and the vast majority of the evaporated solution is condensed, with only a very small amount of non-condensable gases being expelled by the vacuum pump.
It is also related to the saturated vapor pressure. The W3 vacuum pump is generally selected based on experience.
You’re right. How is it calculated? What are the methods for estimation and precise calculation?
Pumping time = Volume of the container to be evacuated / Vacuum pump pumping speed * Lgp/p1 * 2.3
I asked that the vacuum capacity is related to the pump’s blades and cavities; if a certain level of vacuum is required
1. Volume and time required to reach stability after startup 2. Estimation of system air leakage rate
Reply to 8# 1210: How was it solved? What calculation formulas does the original poster have? Please give me some advice!
I really can’t remember how it was solved back then; was it by estimating the vacuum pump model based on the vacuum interface of the equipment?
For continuous operation calculations, use PV=nRT. Use when available: V = m3/min*ln(p1/p2). The issue of air leakage from the system must be taken into consideration. The leakage amount depends on the type and length of the sealing surface. Is that so? Where does the molar flow rate n come from?