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I have a 10-ton reaction vessel that requires the solution to be heated to 80 degrees during the reaction. If a steam boiler is used for heating, how much coal would be needed to reach this temperature?
To be precise, heat balance calculations require parameters such as the heat capacity of the solution, temperature difference, mass (volume), steam pressure, saturation status, return water pressure, boiler thermal efficiency, and the calorific value of the raw coal. Roughly, it’s about 200 kg.
To be honest, your question has many flaws, and only a rough calculation can be done. The reasons are as follows: 1. The initial temperature of the reaction solution is unknown. 2. The specific heat capacity of the solution is unknown. 3. The type of coal burned is unknown. (Assuming the coal being burned is standard coal with a calorific value of 7,000 kcal/KG, the specific heat capacity of the solution is 4,200, which is the same as that of water, and the temperature increase of the solution is 80 degrees) Then the following calculations can be made: 1 calorie refers to the amount of heat absorbed or released when 1 KG of pure water has its temperature increased or decreased by 1 degree. So, 7000 kilocalories represents the amount of heat absorbed when the temperature of 7000 KG of pure water increases by one degree. Therefore, M = 10000*80/7000 = 114 KG. Of course, this is under ideal conditions with no heat loss; in reality, factors such as steam pressure, return water pressure, and the boiler’s thermal efficiency must also be taken into account, as these can all lead to heat loss. So the 200KG mentioned above is roughly in that range as well.
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