About standard solution
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Dear classmates, I am studying* When, I encountered such a question: To prepare 1+5HCl solution, add water () mL to 10Ml6Mol/L hydrochloric acid solution. The result I got was 10 mL and the answer was 20 mL. Is there any expert who can please help me? Thank you very much!
1+5 HCl refers to a hydrochloric acid solution obtained by adding 5 volumes of water to 1 volume of commercially available concentrated hydrochloric acid. To prepare 1+5 HCl from 5 mL of commercially available concentrated hydrochloric acid, 25 mL of water must be added. The concentration of commercially available concentrated hydrochloric acid is about 12 mol/L, and 6 mol/L hydrochloric acid is equivalent to 1+1 HCl. 10 mL of 6 mol/L hydrochloric acid is equivalent to 5 mL of commercially available concentrated hydrochloric acid + 5 mL of water, so to make it into 1+5 HCl, 20 mL of water needs to be added.
1+5mol/LHCl=12/6=2mol/LHCl 2V=6* 10V=30 30-10=20
Thank you everyone, I understand, it was a small mistake in understanding, thank you again.
Learned the problem-solving methods on the second floor. Thank you.