2/1

H2S-2SO2 =0

The ideal ratio of H2S and SO2 to generate sulfur is 2: 1. The proportional analyzer analyzes the difference between H2S-2SO2, and the difference is fed back to the fine-tuned air flow control of the main reactor to achieve optimization of air distribution.

(1) Control the air distribution volume so that about 65% of the hydrogen sulfide undergoes a high-temperature reaction and is converted into elemental sulfur, and 1/3 of the remaining H2S is converted into SO2. Is this correct? Is this the legendary 2/1? (2) The air distribution volume is only enough to convert 1/3 of the H2S into SO2, and the rest is converted into elemental sulfur through thermal reaction. Is this correct? Is this also the legendary 2/1? This post was last edited by Ma Hai on 2009-3-15 20:24 ]

In the reactor, H2S mainly undergoes the following reactions:: 1/3H2S+O2→1/3SO2+H2O 2/3H2S+1/3SO2→S2+H2O The second reaction is a reversible reaction, and the equilibrium conversion rate in the reactor is usually about 65-70%. During the reaction process, under normal circumstances, when H2S and SO2 are controlled at 2/1, the equilibrium conversion rate is the highest. H2S+O2→S2+H2O is the sum of the above two reactions.

Both statements are not very accurate. My understanding is to control the air distribution volume so that about 65% of the hydrogen sulfide undergoes a high-temperature reaction and is converted into elemental sulfur, and to control the concentration ratio of hydrogen sulfide to sulfur dioxide in the exhaust to be 2: 1. Create good conditions for the subsequent catalytic reaction in the reactor

The Claus partial combustion method involves two reactions namely: 1. high temperature reaction: Sixty-five percent of the hydrogen sulfide is converted into gaseous sulfur in the reactor. Of the remaining 35 percent, one-third of the hydrogen sulfide is converted into sulfur dioxide and two-thirds remains unchanged. 2. catalytic reaction: That is, one-third of the remaining 35% hydrogen sulfide is converted into sulfur dioxide and two-thirds of the hydrogen sulfide remains unchanged through an exothermic reaction under the action of a catalyst.

The discussion is not intense enough and the opinions are not consistent. I hope authoritative people can come up with authoritative answers. I only know that hydrogen sulfide will completely decompose at 600 degrees. :lol

Both statements are incorrect. The first is air distribution control. The air distribution volume should allow one-third of the hydrogen sulfide to be converted into sulfur dioxide, so that the ratio of hydrogen sulfide to sulfur dioxide in the system is 2:1. Whether in the high temperature section or the catalytic conversion section, 2:1 can maximize the conversion of hydrogen sulfide into sulfur.

According to the air distribution of 1/3 of the conversion of H2S to SO2, the reaction of conversion of H2S to SO2 proceeds completely. The reaction of H2S and SO2 is a reversible reaction. In the flame reaction zone under the conditions of the combustion furnace, the conversion rate is 65%~70%. This post was last edited by Ma Hai on 2009-3-25 21:54 ]

You can think of it this way, H2S reacts with O2 to form S and H2O. The purpose of O2 is to capture the H2 in H2S to form H2O. The ideal ratio is 2 parts of H2S and 1 part of O2 to produce 2 parts of H2O. What should we look at when we examine how this reaction proceeds? We don't look at the process, we only focus on the ratio of H2S and O2 in the exhaust gas after the reaction, and the O2 after the reaction exists in the form of SO2. So we control the ratio of H2S to SO2 in the exhaust gas to 2: 1 is to hope that the process gas can also follow the magnitude 2 during the reaction.: 1 way to react.

The principle of H2S/SO2=2/1 is the clause reaction (2/3H2S+1/3SO2→S2+H2O). Different process methods have different meanings.: 1 Combustion method: All raw gases enter the combustion furnace, and the air distribution volume is controlled so that H2S/SO2=2/1 in the process gas. 2 diversion method: 1/3 volume of H2S is sent to the combustion furnace, and is completely burned with air distribution and converted into SO2, which is mixed with the remaining 2/3 H2S and enters the catalytic reaction section. 3 Direct oxidation: The preheated acid gas and air are mixed into the catalytic reaction, and the added air is required to convert 1/3 of the volume of H2S into SO2.

so called 2: 1 is given according to the chemical equation: 2H2S+SO2==2/3S2+2H2O: In this way, the maximum sulfur conversion rate can be obtained, and the air distribution is to achieve this optimal conversion rate. Generally, 1/3 of the H2S is completely burned to generate SO2 and then reacts with H2S to obtain the best sulfur recovery rate.

1/2 is for the entire Klaus reaction. Because you ultimately need to convert the hydrogen sulfide into sulfur. Don't think too much about the details. The most important thing is to consider the overall situation

According to the reaction formula 2H2S+SO2——3/nSn+2H2O and the theoretical basis that this reaction is a reversible reaction, when the ratio of H2S to SO2 is 2: At 1, the conversion rate of the reaction is the highest and most complete. To make H2S/SO2=2/1, it can only be achieved by adjusting the air distribution of the sulfur furnace. Theoretically, during the sulfur recovery reaction process, about 2/3 (65%-70%) of H2S directly reacts thermally to generate S, and 1/3 of the remaining 1/3 H2S, or 1/9 of the total amount, reacts to generate SO2, so that the ratio of H2S to SO2 in the tail gas is 2: 1. Claus reaction occurs under the action of catalyst. (1) H2S + 1/2O2 → S + H2O 1/2 mol of O2 is consumed to generate S from 1 mol of H2S, and O2 is consumed to generate S from 2/3 mol of H2S = 2/3×1/2=1/3 mol. (2) H2S + 3/2O2 → SO2 + H2O 1 mol of H2S consumes 3/2 mol of O2 to generate SO2, and 1/9 mol of H2S consumes the amount of O2 to generate SO2 = 1/9×3/2=1/6 mol. In the above two reactions, the total amount of O2 consumed to generate the target product from 1 mol of H2S is 1/3+1/6=1/2 mol, that is, the ratio of H2S to O2 is 2. Since the O2 content in air is 21%, the ratio of H2S to air should be (1/2)/21%=50/21=2.381. That is to say, 1m3H2S needs to be equipped with 2.381m3 of air. Calculated based on the acid gas volume entering the device being 1000m3 and the H2S content being 70%, the air distribution volume = 1000×70%×2.381=1666.7m3

It’s not just a matter of remembering 2.381, but in actual operation, the air distribution is 3-4 times when the H2S content is 80%. ?

The acid gas enters the sulfur-making furnace, and the H2S with an acid gas concentration of about 65% is converted into elemental sulfur in the air distribution. 1/3 of the remaining H2S is converted into SO2, and the hydrocarbons in the acid gas are completely burned to generate CO2 for air distribution. Suppose the acid gas flow is V, the concentration is a%, and the hydrocarbon content is b%. According to the reaction: H2S+1/2O2==S+H2O, H2S+3/2O2==SO2+H2O, it can be seen that 1mol The complete conversion of H2S into elemental S by combustion requires 1/2 mol of O2. The complete conversion of 1 mol of H2S into SO2 by combustion requires 3/2 mol of O2. Then about 65% of H2S is converted into elemental S, and the remaining (1-65%) H2S is converted into SO2 by 1/3. The O2 required is: V x a% Then the amount of O2 required for complete combustion of hydrocarbons to generate CO2 is: V×b%×(3n+1)/2. After the acid gas enters the furnace, about 65% of the H2S is converted into elemental S, and the remaining 1/3 is converted into SO2. The sum of the amount of O2 required for complete combustion of hydrocarbons in the acid gas to generate CO2 is: 0.5×V×a% + V× b% ×(3n+1)/2 Calculated based on the oxygen content in the air being 21%, the required air volume is: V%/2×100/21× = V/42

I have seen the formula, but I never quite understand it, and it always feels awkward to calculate. If you have time, could you give me a hypothetical acid gas volume and give you an example to calculate it? Thank you! ! ! ! ! ! ! ! ! ! ! :handshake:handshake