【Daily Question 20090311】Parameter Setting of Inverters (V) ?
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When the rated current of the motor is 30A, the output current of the inverter is 0–20mA. The range of the ammeter shown is 0–20mA, corresponding to 0–50A; how should it be set in order to accurately display the motor’s operating current on the ammeter? Summary: Generally, an output current of 20mA from an inverter corresponds to the motor’s rated current; in some cases, it corresponds to twice the motor’s rated current. To enable accurate display of the motor’s actual current on other instruments, there is a parameter known as the output ratio, which can be adjusted to change the current value corresponding to 20mA. In this case, by setting the output ratio to 60%, 20mA will correspond to 50A, allowing the instrument to accurately reflect the motor’s operating current. This post was last edited by lihy on 2009-3-11 20:01]
In my opinion, the output signal of 0 mA should correspond to the lower limit of 0 A, while 20 mA should correspond to the upper limit of 50 A. If there is a corresponding value for the input current, then 30 A should be set to correspond to 12 mA; the upper and lower limits will be the same as those for the output.
Set the current display calibration to 50
Set the current display calibration to 30
In my understanding, an output signal of 0 mA corresponds to the lower limit value of 0 A, while 20 mA corresponds to the upper limit value of 30 A
The inverter current correction is set such that 0 mA corresponds to 0 A, and 20 mA corresponds to 50 A.
It should be that the output signal: 0 mA corresponds to the lower limit of 0 A, and 20 mA corresponds to the upper limit of 50 A :) :)
Change the value corresponding to a gauge range of 20mA to 30
The output signal should be adjusted so that 20 ma corresponds to 50 a
An output signal of 0 mA corresponds to a lower limit of 0 A, while 20 mA corresponds to an upper limit of 50 A. If there is a corresponding value for the input current that can be set, then 30 A can be set to correspond to 12 mA; the upper and lower limits remain the same as those for the output.
After reading the responses from those above, it seems that everyone has mixed together two different concepts, which prevents the formation of a relatively standard answer: the operating current of the motor and the signal transmission current of the inverter. According to the requirements, the target value should be the motor current; its maximum operating current is 50A, and the corresponding transmission signal is a current signal in the range of 0-20mA. This makes the range conversion factor clear at a glance.