In the tannin-based desulfurization process, what does total alkalinity of 0.4N mean? Could someone give some advice?
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What is the relationship between a total alkalinity of 23.85 mg/l and 0.4N?
0.4N is an equivalent concentration; it is no longer in use, and it indicates that the total alkali content in 1 liter of tannin solution is 0.4 gram equivalents.
Total alkalinity 23.85 mg/l? It’s way too low. Total alkalinity (calculated as sodium carbonate) is 23.85 g/l, which is equivalent to 0.45 N!
0.4N = 0.4 mol(OH-)/L; (OH-) = 1/2Na2CO3 + NaHCO3
In the tannin-based desulfurization process, the total alkalinity is composed of Na2CO3 and NaHCO3； The ratio of Na2CO3 to NaHCO3 is about 1/3.
How is 4# wycasia calculated? Could you write it briefly? Thank you
0.4N denotes equivalent concentration; it is now rarely used (although many older factories still employ it). Nowadays, g/l is generally used instead. The conversion factor is 0.4 multiplied by 53, which equals 21.2 g/l.