[Phase 1 of Time-Limited Quick Response Contest] 009 [Completed]
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Rules: 1. If you want to answer immediately, give a score of +1 wealth to floor 1 and write your answer in the “Reason for action” field (only the content within parentheses); see the figure below for details. 2. “*” represents a Chinese character or a digit, and the answer must match exactly to be considered correct. 3. The first person to answer correctly will receive +10 wealth points; please reply in the replies on floor 2 and below to claim the reward ； 4. The scope of questions covers the commonly used standards and experience manuals in the fields of process engineering and piping ； 5. The difficulty level of the questions increases from easy to difficult. 6. Lower-grade students are welcome to participate actively. Question of this issue: 009. The thickness of the insulation layer to prevent burns is calculated based on the surface temperature. The surface temperature of the insulation layer shall not exceed (***) K. Standard answer: 333 Winner: Pseudo Xiao Bao Last edited by hutom123 on 2009-3-25 09:31]
The major case has been submitted to 333; the thickness of the heat-insulating layer to prevent scalding is determined based on the surface temperature. The temperature of the outer surface of the insulation layer shall not exceed (333) K. This post was last edited by Pseudo Xiaobao on 2009-3-15 11:11]
According to clause 9.1.2 of GB/T 8174-2008, a failure is deemed to occur when the surface temperature exceeds 323 K (with an ambient temperature of 298 K); therefore, I believe 323 K is the correct value.