How to calculate the water volume required for directly **cooling superheated steam? Please help
Thread Content
Dear teachers, in the production process, it is necessary to pass 1 ton of superheated steam with a temperature of 420°C and a pressure of 2.45 MPa through a temperature and pressure reduction device, using water at 100°C to do so; this results in steam with a pressure of 0.20 MPa and a temperature of 125°C. Theoretically, how much water at 100°C is required?
Calculate the enthalpy difference between inlet and outlet; by dividing this value by the vaporization latent heat of water at 125°C, the amount of water required can be estimated.
By setting up two equations based on equilibrium and solving them together, the amount of water needed for temperature reduction can be determined. Let the amount of water required for temperature reduction be x: then, (Amount of steam entering + Amount of water used for temperature reduction x) = Amount of steam exiting. Additionally, (Enthalpy of steam entering × Amount of steam entering + Enthalpy of water used for temperature reduction × Amount of water used for temperature reduction x) = (d + x) × Enthalpy of steam exiting. By solving these equations, the value of x can be found.
Has the poster made a mistake? A pressure of 0.20 MPa and a temperature of 125°C correspond to water. Is the specified condition absolute pressure or gauge pressure?
Calculating the enthalpy difference is simple: the heat absorbed by water is equal to the heat released by steam
Under the proposed pressure conditions, all calculated as absolute pressure, 248 Kg of water at 100°C is required.
It’s gauge pressure; I forgot to mention that, my apologies