How long does it take to heat 180 kg of water with a 17.8-meter steam coil?
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Parameters of the steam coil: middle diameter 437 mm, number of turns 13, spacing between turns 30 mm. It was designed using CAD for 3D modeling; the length of the coil is 17.808 meters. The tubes used are 25X2 diameter steel pipes, and the heat exchange area is calculated at 0.07854 square meters per meter, resulting in an area of 1.4 square meters. The volume of water that needs to be heated is 0.18 cubic meters, which corresponds to 180 kg. Question: Given these conditions, how long will it take to heat the water to 95 degrees using this steam coil? (Sorry, I handed all the thermal calculations back to the teacher.) This post was last edited by ningyong58 on 2009-3-20 at 13:25
I think this heat exchange time should be determined based on the size of the equipment and the flow rate of the process fluid. The fluid enters through one port and exits through another, and that time period is presumably the heat exchange time. Specifically, detailed calculations are needed
It should first be calculated that the heat required to raise 180 kg of water from 20 degrees to 95 degrees is approximately 13,500 kcal. Then, the heat transfer rate per unit time is calculated using the basic heat transfer equation Q=KA(t1-t2), and the required time is obtained by dividing the necessary amount of heat by Q. However, you should also provide the average temperature of the hot fluid.
The original poster listed a bunch of conditions, which seem comprehensive, but the most crucial one was missed: the steam conditions – what temperature and what pressure should the steam have? Saturated? Overheating?