Steam heat exchange calculation
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When calculating heat transfer with saturated steam, how is the heat released when the temperature drops from 249 degrees to 190 degrees calculated? It’s all saturated steam.
Q=ΔIm; as mentioned on the first floor, one needs to look up the enthalpy values at various temperatures and then subtract them
It seems incorrect; using specific enthalpy for the calculation is wrong
The conditions are not met! Is there a phase change? ? If it is saturated steam, a change in temperature will inevitably lead to a change in steam pressure, along with a phase change.
The pressure corresponding to saturated steam at 249 degrees is 39 kilograms, with a heat capacity of 2801 KJ/KG. The pressure corresponding to saturated steam at 190 degrees is 12.5 kilograms, with a heat capacity of 2785.7 KJ/KG. It’s hard to imagine using steam at such high pressures for heating; if it’s just a theoretical calculation, and no phase change occurs (no condensation water is produced), then one can simply multiply the difference in heat capacities by the mass