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Total heat loss?

2009-03-26View Original

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If the length of a pipe is known to be L and its inner diameter is d, then Q' represents the heat loss per unit length of the pipe for the fluid flowing from the starting point T1 to the ending point T2. If a pump has a capacity of 2000 m3/h and is used to transport this product through these pipes, how much heat will be lost in 1 hour? Assume that Cp remains unchanged. The density p also remains unchanged.
Reply #22009-03-31
Be more proactive, everyone! I’ve solved it now, haha. It was just a mistake in the calculation of the points.
Reply #32009-03-31
This problem isn’t that troublesome. OK
Reply #42009-06-10
The original poster can calculate the specific heat of the fluid using the formula Q=MCp(T1-T2), and the result will be in KG/S*3600, representing the heat loss per hour. I’m not sure if it’s correct

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