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Regarding the uniformly distributed load in CEASARII

2009-03-28View Original

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I have a question for everyone: regarding the uniformly distributed load input option in INPUT in CEASARII, under what circumstances is it necessary to enter a uniformly distributed load? How is this value calculated?
Reply #22009-03-30
Depending on the actual conditions, if there is a uniformly distributed load, it must be entered, such as wind, snow, earthquakes, etc.!
Reply #32009-03-30
Thank you to dwscu and lijia*n. I also want to ask: if the wind load has been entered separately, does the uniform load refer only to snow or earthquakes? If it’s snow, is the force of the uniformly distributed load equal to the weight of the snow? If it’s an earthquake, then how is the force of the uniformly distributed load calculated?
Reply #42009-03-31
Specifically, it needs to be edited in the operating condition editor according to the actual situation; not all types of loads are included as some people think – there are Sustained cases, OCC cases, and so on!
Reply #52009-03-31
A uniformly distributed load does not refer only to snow or earthquakes; uniformly distributed external forces are also possible. If it’s snow, then is the force of the uniformly distributed load equal to the weight of the snow? That’s right. In the case of an earthquake, the force of the uniformly distributed load is expressed as acceleration; the specific value must be determined according to the building seismic design codes.
Reply #62009-03-31
Thank you to mliu-5 and lijia*n for their patient explanations :) I understand now; the uniformly distributed load expressed in terms of acceleration that appeared in the stress report I saw was related to seismic analysis
Reply #72009-04-11
When using a uniform load, pay attention to its inheritance property: once a uniform load is applied to a certain element, it is applied to all subsequent elements as well, until you set the uniform load to zero.

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