Problems with stripping section of catalytic cracking unit
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I saw this passage in the book: When the to-be-generated catalyst falls into the stripping section, the hydrocarbons adsorbed on the surface of the catalyst, the hydrocarbon vapor in the pores of the catalyst, and the hydrocarbon vapor entrained by the catalyst also enter the stripping section. First, stripping water vapor is used to remove the hydrocarbon vapor entrained between these catalyst particles. The ratio of stripping water vapor is 2~5lb/1000lb (2~5kg/1000kg). The ratio 2~5lb/1000lb (2~5kg/1000kg) here refers to the ratio of which one to that one? This post was last edited by Yun Zhonggong at 2009-4-3 09:48 ]
kg/1000kg is a ratio relationship, which refers to the amount of steam used per ton of feed； 2~5 are numerical values, which really represent percentages. The complete expression is: 2~5 (w%) kg/1000kg. So what it means is: Use 0.02~0.05kg of steam for every 1kg of feed. This post was last edited by zhifengshen on 2009-4-3 10:53 ]
It should be the ratio of the amount of stripping steam to the amount of catalyst to be generated.
I think it should be the ratio between steam and catalyst circulation, that is, the ratio between steam per unit time and catalyst entering the stripping section per unit time.
is the ratio between steam and feed volume.
It should be the ratio of steam to catalyst circulation. The 700 tons/hour catalysis is estimated to be 3500kg/h based on the above ratio, which is consistent with the actual situation and should be correct.