Is the ammonia oxidation process calculated using the ideal gas law?

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Hello everyone: I’m not majoring in chemical engineering, but my thesis requires me to carry out chemical engineering calculations for the first time – specifically, to calculate the energy requirements of the medium-pressure ammonia oxidation process. There is one issue: according to chemical engineering principles, the molar amounts of ammonia and air are supposed to be calculated using the ideal gas law. However, using this method, the ammonia-to-air ratio obtained is quite high. The value of MNH3 is calculated as follows: MNH3 = (PNH3 * VNH3) / (R * TNH3) = (0.58 MPa * 5438 m3) / (8.314 * 373) = 1,017,064 Kmol； MAIR = (PAIR * VAIR) / (R * TAIR) = (0.45 MPa * 21,819 m3) / (8.314 * 513) = 2,302,077.7 Kmol. The molar ratio (standard volume ratio) is almost 30%, which is far above 9.5%. I’m not sure whether this calculation is correct and reasonable; if it is, then are there any issues with these values? :funk: :funk: :funk: :funk: :funk::