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I would like to ask what is meant by 1000 tons for a rammer, and how is it calculated? It seems to say that the torque required is around 10,000 N.M or something like that? What is the conversion ratio between tons and NM? What is its relationship to the weight of the hammer, the lifting height, and the base area? Thank you, waiting online
It might be the instantaneous pressure per unit area exerted by the rammer when compacting the ground, but your figure seems too high, OP.
The numerical value isn’t an issue; it’s his method of conversion that matters
I hope the experts will kindly share their insights~~
I wonder if the gravitational potential energy of an object when it falls to the ground is what’s referred to as 1000 Nm? Is w=mgh? Those 10,000 NM represent the work done when a 100 kg object is raised 10 meters before falling to the ground; it’s an idea that is fairly close to the values mentioned in everyday discussions. Maybe it’s correct, but the technical requirement for pile driving in the end is bearing capacity, right? If objects of the same weight land on surfaces with different areas of contact, then the pressure exerted must also be different, right? Is it related to the base area? From the perspective of forces, theoretically, according to the momentum theorem mv=ft and p=f/s, the pressure exerted on the ground at the moment of impact is roughly equal to the ground’s bearing capacity But how long is this effect lasting? 1 second? So what is the relationship between that pressure and what is commonly referred to as tonnage? I think I’m overthinking it, aren’t I? m=ρsh, so p=ρshv/ts=ρhv/t – is it related to the height of the hammer head? . I’m almost going crazy. . I think I’m definitely overthinking this. . . Our engineers only know the practical situation; they don’t understand theory. . . I’m confused. Please, someone who knows the answer can tell me. In the above, the letters represent the following: w – work; m – mass; g – acceleration due to gravity (taken as 10); h – height; v – velocity; f – force; t – time; p – pressure; s – area over which the force acts; ρ – density of the hammer head. The last edit to this post was made by NO.1 on 2009-4-9 at 18:28
The above are just my guesses; I hope some experts can give an opinion. . Thank you. Everyone, please also participate actively in the discussion to pool our ideas
Which 1000 tons refers to the nominal pressure? Logically, the unit of pressure should be pascals, but in calculations it is determined based on unit area; therefore, the area isn’t important. Pressure divided by area gives stress, which is why it is also referred to as the pressure of 1000 tons. This 1000 tons represents the output capacity of concrete. Last edited by *QIU on 2009-4-15 16:09.]
Let me correct that: pressure multiplied by area equals force. It’s probably a typo on your part. The question is: can one square meter of area support an object weighing 1000 tons? If you could reply, what is meant by bearing capacity here? What is the relationship between the weight of the hammer used during pile driving and the lifting height? I hope you will kindly offer your guidance
The building lost power just now; I will get back to you later. The 1000 tons mentioned by the original poster is likely an energy unit, with the unit being KN/m. It’s not as complicated as the poster thought; I was wrong too. The value of 1000 tons can be determined as follows: assuming the weight of the rammer’s hammer is 20 tons and the lifting height is 5 meters, then 20T*5m*9.8 = 980 KN/m, which is roughly equivalent to 1000 KN/m. The formula is weight of the hammer * lifting height * 9.8 = this energy unit. The poster can ask about the weight of the rammer’s hammer and the lifting height on site, and then calculate it
I’ll take the time to ask whether the height and weight are indeed as such. Also, the unit here seems a bit incorrect; should it not be divided by an area unit (㎡)? If that’s the case, then it will make sense
10000N.M should refer to kilonewton-meters, right? You’ll need to look up the specific conversion yourself; I think your units aren’t quite correct either.