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Calculation of indirect condensation heat transfer

2009-04-14View Original

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May I ask, half of the gas is condensed by water, while the other half remains uncondensed. How is this heat exchange process calculated? Thank you for the help
Reply #22009-04-14
It can be calculated using software. Manual calculation: For calculating the film heat transfer coefficient on the steam side, the total amount of steam is used, and a 50% area margin is applied.
Reply #32009-04-14
The most important thing is to determine whether the gas that has not been condensed is a non-condensable gas. If it is a certain type of medium, information on it can be found in standard heat exchange textbooks. If it is a non-condensable gas, it is necessary to calculate separately the heat exchange area required for the gas phase and that required for condensation; generally, the heat exchange area needed for cooling the gas phase is much larger than that required for condensation.
Reply #42009-04-14
There are calculation software available to check; doing it by hand is too troublesome.
Reply #52009-04-15
Are you referring to the condensation problem involving non-condensable gases? If so, the calculations are quite complex; for manual calculations, you can refer to Method 11.6 for designing cooling condensers on page P145 of the book \"Heat Exchanger Design Manual\" by Hidetaka Ogiba.
Reply #62009-04-15
For pure substances, the calculations are carried out using the formulas in Chapter 4 of the heat exchanger design manual (by Qian Songwen). For substances containing non-condensable gases, the calculations follow the guidelines provided above. When there is a phase change, the latent heat must be taken into account; in the absence of a phase change, only the sensible heat needs to be considered. It is important to note that the partial pressures corresponding to each component differ

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