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I’m facing a problem now: the 24 kilograms of liquid propylene at 40 degrees Celsius that comes in from outside is reduced in pressure by the control valve, resulting in 10 kilograms. In my simulation, the temperature is likely to drop to 5-6 degrees Celsius (I think), and the substance will become a two-phase mixture of vapor and liquid. But the pressure reduction in a steam control valve works like this: 4 kilograms of saturated steam have their pressure reduced to 2.4 kilograms. My colleague said that the temperature remains unchanged after the pressure reduction, meaning that the steam becomes superheated as a result. I have some doubts about this; I’m curious to know what others think! ! ! ?
According to the equilibrium equation for an ideal gas, if the volume remains constant, the temperature decreases; whereas if the volume increases after passing through a valve, the temperature can be kept constant. :lol
According to the equilibrium equation for an ideal gas, if the volume remains constant, the temperature decreases; if the volume increases after passing through a valve, then the temperature can be kept constant
According to the equilibrium equation for an ideal gas, if the volume remains constant, the temperature decreases; whereas if the volume increases after passing through a valve, the temperature can be kept constant.
The temperature of saturated steam should also decrease after pressure reduction; it can be calculated using an isenthalpic process. The decrease isn’t significant, and the resulting temperature will be lower than that corresponding to 4 kilograms of saturated steam, but higher than that corresponding to 2.4 kilograms of saturated steam – it remains superheated steam.