Water output during temperature-rise reduction of synthetic copper-based catalysts

There are two stages: water release upon temperature increase and water release during reduction. Most imported catalysts contain little to no physical water, as well as minimal chemical water. However, domestic catalysts contain both types of water, with significant variations in the amount of physical water; the catalysts produced by Nanhua Institute have less physical water, while those from Southwest Institute have more.

Calculation of water output: CuO + H2 → Cu + H2O 79 18 A B B=18*A/79 (chemical water) C=total amount of catalyst*water content in the catalyst (physical water) A:CuO content in the catalyst B:amount of water generated by the reaction between CuO and H2 Total output=chemical water+physical water

By accurately calculating the chemical water output and consulting the catalyst manufacturer to find out the physical water output, it is possible to calculate the water output during the heating and reduction process

You need to determine the content of each component based on the specific model of your catalyst. Then, calculating based on the third floor gives that result

Imported catalysts contain little physical water and also little chemical water, while domestic catalysts have both physical water and chemical water. The South Chemical Research Institute has less physical water, while the Southwest Research Institute has more. The amount of water produced during the temperature-induced reduction of copper-based catalysts depends not only on the specific type of catalyst used but also on the reducing agent employed in the reduction process. Using pure hydrogen as the reducing medium and nitrogen as the carrier gas results in a higher water output. It is also the usual reduction method. But nowadays, mixed reduction media are also being used; for example, it is common to employ syngas containing hydrogen and carbon monoxide to reduce methanol catalysts. With pure hydrogen as the reduction medium, the water output per unit of methanol catalyst at the Southwest Research Institute is approximately 180 kilograms of water. The calculation method is: based on the physical water content and copper oxide content data provided in the quality inspection reports from the catalyst manufacturers, it is determined that one molecule of copper oxide produces one molecule of water.

If process gas is used for heating and reduction, CO must be taken into account when calculating the chemical water; no water is produced when this portion of copper oxide is reduced.

Before carrying out the heating and reduction process for copper-based methanol synthesis catalysts, it is necessary to calculate the theoretical water output in advance, as a reference to determine whether the actual water output during this process is sufficient. The method for calculating the theoretical water output is as follows: The water released by the catalyst during heating and reduction consists of two components – one is the physical water output A, which refers to the water contained within the catalyst itself; the other is the chemical water output B, which results from the reaction between hydrogen and the oxygen in copper oxide. To determine the theoretical water output of the catalyst, these two amounts must be added together.