Calculation of the volume of horizontal storage tanks
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This post was last edited by sunjl1981 on 2013-1-7 00:18. Dear sea friends, how is the capacity of a horizontal storage tank calculated? Using the volume calculation formula, the volume of the cylinder is 48.21 m3, and the volume of the standard elliptical head is 2.3 m3; thus the total volume is 50.51 m3. Yet when using software for the calculation, the total volume comes out to be 53 m3. Is there something that has been overlooked in the calculations? Could that expert give some guidance? # + + .
This post was last edited by yakui on 2009-6-3 09:03. The simplest way is to use calculus formulas and enter them manually in an EXCEL spreadsheet. Write down the diameter and total length, and I’ll try to calculate it for you.
Thank you. The length of the storage tank is 9000 mm, the height of the straight sides is 40 mm, the depth of the elliptical head is 650 mm, and the inner diameter of the storage tank is 2600 mm. Salute to you! :handshake
My calculation gives 52.8. Did the original poster omit the volume of one end cap when making the calculation?
Thank you for the support from the fifth floor. How did you do the calculation? Could you please share the method? My email address is hansr0508@163.com.
I’ll tell you the calculation method, thank you.
Replying to the original poster: I calculated it manually to be 52.7856 M3, while the software gave a value of 52.8098 M3. The volume of the standard elliptical head (EHA type) is 2.5 M3. Did the poster make a mistake in entering the cylinder length when using the software? The length specified in the software should include the height of the change in volume.
This post was last edited by 181128425 on 2009-6-3 13:10, edit #8 #yakui
You can check past issues of magazines on the chlor-alkali industry or polyvinyl chloride; articles on this topic have been published there.
This calculation is quite simple. The volume of the cylinder, without considering the end caps, is calculated using the formula for a cylinder: V1 = 0.25 * PI() * 2600^2 * 9000 / 10^9. The result is 47.78 m3. As for the volume of the standard elliptical end caps, it can be determined by referring to the data in standard JB/T 4746-2002 or by using the formulas provided therein; the resulting value is V2 = 2.51 m3. Since it is a horizontal storage tank, it should have two end caps. The final calculation result is: V = V1 + V2*2 = 52.80 M3. What’s actually difficult is calculating the volume of the medium inside the tank at a certain interface; there are many similar papers in journals, and the “filling coefficient” function available in “Equipment Tong 2000” can also be used for this purpose.