How is the outlet pressure of a centrifugal pump converted into head?
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How is the outlet pressure of a centrifugal pump converted into head? Personally, I wonder: how many meters does 1 kilogram of pressure equal? Is it based on the formula pressure equals density times g times h? Thank you all!
This post was last edited by yq Hao on 2009-7-6 at 20:44. The equation relating head to pressure is: H = (P2 – P1) / ρg, where P2 is the outlet pressure in kPa, P1 is the inlet pressure in kPa, ρ is the specific gravity of the liquid, and g is the acceleration due to gravity. In the case of a water pump, if the pressure difference between the inlet and outlet is 1 kilogram, then the head is 10 meters.
This post was last edited by tear1102 on 2009-7-6 at 19:31. Head ≈ (exit pressure – inlet pressure) ÷ specific gravity; you mentioned that 1 kilogram is equivalent to 10 meters.
I’m also confused about this question. Thank you!!
The pressure difference equals density multiplied by gravitational acceleration multiplied by height (head)
Pressure difference (MPa) = Density (Kg/m3) * Gravity acceleration (9.8 N/Kg) * Head (m). Therefore: Head = Pressure difference / Density * Gravity acceleration. The head is equal to the pressure difference divided by density and gravity acceleration, using a consistent set of units. So the one on the 3rd floor got it wrong
So, should we use head as the criterion or pressure difference as the criterion when making a selection?
The pressure difference equals the acceleration due to gravity multiplied by density multiplied by head
Head is related to the structure of the centrifugal pump, and has little to do with material properties. Within the head range of the device, it is directly proportional to the outlet pressure.
Bro, you’re wrong too; the pressure unit in your formula is Pa
Haha, the discussion is intense! I agree with the view from the second floor.