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Why does a higher alcohol-to-ammonia ratio result in a higher total ammonia production?

2009-08-12View Original

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In the production of dihydric alcohols, if the methanol yield is high, why is the overall yield also high?
Reply #22009-08-13
This statement has certain limitations, as the original process for producing polyol from ammonium carbonate was constrained by the need to use ammonia to remove carbon dioxide; therefore, the alcohol-to-ammonia ratio could not be too high, otherwise there would be an ammonia imbalance; In current production processes, ammonia production is no longer affected by decarburization. As a result, in the production of hydrazine, not only has the pressure range shifted from medium pressure to low, medium, and high pressure, but also the ratio between ammonia and hydrazine – or between hydrazine and ammonia (both of which can generally be referred to as hydrazine derivatives) – is no longer determined by such ratios; instead, it is controlled by market factors and by the configuration of the facilities owned by the companies themselves ; What the original poster mentioned about a high alcohol-to-ammonia ratio and high total ammonia is sometimes evident as well. With a constant compressor, increasing the alcohol production results in better energy efficiency and lower resistance; the gas flow rate in the compressor’s gas section is relatively higher, leading to a slightly higher total ammonia production.
Reply #32009-08-13
The last edit to this post was made by ZZJJAA70 on 2009-8-13 at 10:21. It’s certain that a higher alcohol-to-ammonia ratio leads to a higher overall yield, as the original poster didn’t specify that the reaction takes place under fixed conditions of gas volume. In this case, a higher alcohol-to-ammonia ratio results from an increase in the amount of effective gas involved in the reaction, which in turn increases the gas generation load. If this factor is excluded, as mentioned above, the compressor will certainly see an increase in alcohol production; it becomes more energy-efficient and experiences less resistance. The gas flow rate in the compressor’s gas section increases slightly, resulting in a slightly higher total ammonia output. It should be noted that a higher alcohol-to-ammonia ratio also leads to an increase in CO2 levels in the gas before alcohol production, which in turn increases the overall output. However, all of this occurs on the condition that hydrogen is consumed.
Reply #42009-08-13
The reason is quite simple: if the gas source required for the alcohol-ammonia process is to be used for ammonia synthesis, it must undergo methanation first. Methanation is a reaction in which hydrogen reacts with carbon to produce methane, which inadvertently consumes the hydrogen in the syngas, thereby reducing the amount of usable gas. The alcohol-ammonia process involves the reaction of CO2/CO with hydrogen to produce methanol; the amount of hydrogen consumed is the same as in the methanation process, and the ammonia yield is identical, with additional methanol being produced. Therefore, the sum of the two is definitely higher than the output of the pure ammonia synthesis process.
Reply #52009-08-14
In semi-water gas, nitrogen is obtained directly from the air; increasing methanol production reduces the amount of nitrogen added, thereby raising the hydrogen and CO content in the semi-water gas and improving its quality.

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