Choose the cable according to the power of the motor. Is there any advice?

This post was last edited by zhaohh3211 on 2010-7-26 17:11. According to the rated voltage, multiply the rated voltage by two and a half by nine, and then subtract one as the number goes up. Thirty-five is multiplied by three point five, and when pairs are in a group, point five is reduced. If conditions change, discounts will be added, and copper upgrades at high temperatures will be 10% off. The number of threaded pipes is 2, 3, 4, 876%, full load flow. Don’t know what to think about this? Is it what you need.

Motor 1KW is calculated as 2A current. You can refer to the cable carrying capacity mentioned on the second floor. If you want to be safer, you can choose a cable that is one level larger than the calculation.

Yes, I hope there is better information.

The statement on the third floor is an estimate of a three-phase motor. A single-phase motor is approximately 1KW and has an estimated current of 5A.

Tips for wiring motors: 2.5 plus three, 4 plus four ； 6 followed by six, 25 five ； 120 wires, with hundreds indicating that this formula is for wiring a three-phase 380 volt motor. The conductors are aluminum core insulated wires (or plastic wires) laid through pipes. First, we need to understand the arrangement of general motor capacities (kilowatts): 0.8 1.1 1.5 2.2 3 4 5.5 * * 1O 13 17 22 30 40 55 75 100 "2.5 plus three" means that 2.5 square millimeters of aluminum core insulated wires are laid through pipes and can be equipped with "2.5 plus three" kilowatt motors, that is, the maximum motor can be equipped with 5.5 kilowatts. “4 plus four" is a 4 square millimeter aluminum core insulated wire, which is laid through a pipe and can be equipped with a "4 plus four" kilowatt motor. That is, it can be equipped with a maximum of 8 kilowatts (the products only have similar * * kilowatt) motor. “"6 plus six" means that starting from 6 square millimeters, and later can be equipped with "increased six" kilowatt motors. That is, 6 square millimeters can be equipped with 12 kilowatts, 10 square millimeters can be equipped with 16 kilowatts, and 16 square millimeters can be equipped with 22 kilowatts. “25 five" means that starting from 25 square millimeters, the addend changes from six to five. That is, 25 square millimeters can be equipped with 30 kilowatts, 35 square millimeters can be equipped with 40 kilowatts, 50 square millimeters can be equipped with 55 kilowatts, and 70 square millimeters can be equipped with 75 kilowatts. “1 2 0 wires match hundreds" (read "hundreds and two wires match hundreds") means that the motor is as large as 100 kilowatts. The conductor cross-section is not matched with the motor based on the "increased" relationship, but a 120 square millimeter conductor can only be used with a 100 kilowatt motor.

Motor 1KW is calculated as 2A current. You can refer to the cable carrying capacity mentioned on the second floor. If you want to be safer, you can choose a cable that is one level larger than the calculation. The above calculation is based on aluminum wire, and the copper wire should be calculated on the basis of 3A current.

Generally, a 3-phase motor has 1 kilowatt and 2 amps, but you need to consider the starting current of the motor, which is generally 3 times the rated current. Then select the cable according to the carrying capacity of the wire, as determined by the second floor! Single phase motor 1kW 5A calculation!

Tips for estimating the relationship between the current carrying capacity and cross-section of aluminum core insulated wires: 　　Multiply nine by two point five, and subtract one if you go up. 　　Thirty-five is multiplied by three point five, and when pairs are in a group, point five is reduced. 　　If conditions change, discounts will be added, and copper upgrades at high temperatures will be 10% off. 　　The number of threaded pipes is 2, 3, 4, 876%, full load flow. 　　 　　illustrate: 　　 　　(1) The formula in this section does not directly indicate the current carrying capacity (safety current) of various insulated wires (rubber and plastic insulated wires), but expresses it by "multiplying the cross section by a certain multiple" and obtains it through mental calculation. It can be seen from Table 5 3: The factor decreases as the cross section increases. 　　“Multiply two and a half times nine, and subtract one when going up. "It refers to aluminum core insulated wires with various cross-sections of 2.5mm' and below, and their current carrying capacity is about 9 times the number of cross-sections. For example, for a 2.5mm' wire, the carrying capacity is 2.5×9=22.5(A). The relationship between the multiples of the current carrying capacity and the cross-section number of wires starting from 4mm' and above is arranged upward along the wire number, and the multiples are reduced by l successively, that is, 4×8, 6×7, 10×6, 16×5, 25×4. 　　“Thirty-five times three-and-a-half, and minus one-point five in pairs, it means that the current carrying capacity of a 35mm wire is 3.5 times the cross-section number, that is, 35×3.5=122.5(A). For conductors of 50mm' and above, the multiple relationship between the current carrying capacity and the cross-section number becomes a group of two wire numbers, and the multiple is reduced by 0.5 in turn. That is, the carrying capacity of 50 and 70mm' conductors is 3 times the number of sections ； 95, 120mm" wire carrying capacity is 2.5 times its cross-sectional area, and so on. 　　“If conditions change, additional discounts will be applied, and copper upgrades at high temperatures will be 10% off.” The above formula is based on the condition of aluminum core insulated wire and exposed application at an ambient temperature of 25°C. If the aluminum core insulated wire is laid open in an area where the ambient temperature is higher than 25°C for a long time, the current carrying capacity of the wire can be calculated according to the above formula, and then a 10% discount can be applied ； When copper-core insulated wire is used instead of aluminum wire, its current carrying capacity is slightly larger than that of aluminum wire of the same specification. You can calculate the current carrying capacity of one wire size larger than the aluminum wire according to the above formula. For example, the current carrying capacity of 16mm' copper wire can be calculated based on 25mm2 aluminum wire.

What everyone above said is right, I agree.