Calculation of heat exchange efficiency of heat exchangers
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There are two heat exchangers, with a total heat exchange area of 120 square meters. The hot water flow rate can be adjusted to its maximum level (for the heat exchanger), with an inlet water temperature of 43 degrees. The cold water flow rate is around 130 cubic meters, and the inlet water temperature is around 8 degrees. Could you help me calculate how warm the cold water will get after being heated?
I made the following assumptions: 1. There is an ample supply of hot water, so it can be assumed that its temperature does not drop much; the inlet and outlet temperatures of the hot water are both 43 degrees. 2. The K value for water–water heat transfer is between 850 and 1700 W/m2K, so 1000 was chosen. Because Q = K*A*dT = M*C*(T - T0), where K = 1000, A = 120, dT = ((43 – 8) – (43 – T)) / ln((43 – 8) / (43 – T)), M = 130, C = 4.18; T is the value to be found, and T0 = 8. The result is T=27.2 1# Step by Step High
How much is the cold water flow? Your question isn’t clear The flow rate is highly related to the outlet temperature.
2# engineer*a Thank you
Could Engineer 2# help me calculate how many tons of 0.7MPa saturated steam are equivalent to the heat recovered per hour?
The enthalpy of steam at a gauge pressure of 800 kPa is 2773.7, while the enthalpy of water is 720.96; you can calculate it yourself
Is there a standard conversion formula? I want to try that too: lol