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Calculations on azeotrope systems

2009-12-18View Original

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There is a binary azeotropic system simulated using proII; the azeotrope is obtained at the top of the column, while the other component is obtained at the bottom. Why then aren’t the two components in the overhead stream in an azeotic composition?
Reply #22009-12-20
I’m also working on azeotrope systems; let’s discuss it together
Reply #32009-12-24
What system is azeotropic? Only by saying it can everyone study it! The original poster, please describe the problem in more detail!
Reply #42010-01-27
This is related to the settings of your tower; for example, the pressure in the tower – the azeotrope composition changes at different pressures
Reply #52010-01-27
Azeotropic distillation is very complex. Due to the dilution effect caused by the addition of an azeotrope, when using azeotropic distillation to separate an azeotic mixture, the amount of azeotrope added is usually greater than the mass calculated based on the azeotic composition. Suppose x kilograms of A and y kilograms of B form an azeotrope. Now, using A as the azeotrope agent to separate a mixture of B and C, h kilograms of A should be added based on the azeotopic composition of A and B. However, the actual amount of azeotrope agent added is usually greater than h; let this amount be l. Up to this point, the system can be considered to consist of the following components: l-h (i.e., the excess azeotrope), the azeotrope formed by A and B, and component C. Assume that the boiling point of the azeotrope is I, the boiling point of the azeotrope formed by A and B is J, and the boiling point of component C is K. And there is the following relationship: I
Reply #62010-01-27
Theoretically, there should be one outlet at the top and one at the bottom of the tower from which a product with a composition close to that of an azeotrope is obtained; the degree of closeness depends on the separation efficiency. That’s how I understand it: when two substances are mixed together and form an azeotropic system, at certain temperatures and pressures the azeotrope has a specific composition. If the mixing ratio of the two substances happens to be exactly that azeotic composition, then it’s impossible to separate these two substances. In such cases, this azeotrope can be considered as a single substance. But generally, it is not exactly the azeotropic composition with one component in excess; in such cases, the system can be considered to consist of the azeotrope and the excess component, and then understood using conventional distillation principles. Azeotropes have an azeotopic boiling point, while the excess component has its own boiling point; if these two values are close to each other, it is necessary to increase the reflux ratio and the number of tower plates in order to improve the separation accuracy of the azeotrope and the excess component. If the conditions are not favorable, then of course both the material coming from the top and the bottom of the tower will be a mixture of azeotropes and excess substances, and the azeotropic composition cannot be obtained.
Reply #72010-01-27
Try the following methods: 1. Minimize the amount taken from the tower top, 2. Use a high reflux ratio, 3. Use as many theoretical plates as possible. That should be sufficient

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