Methanol synthesis reactor simulation
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When I simulate the methanol synthesis tower, why is the calculated heat value negative? Also, what does the second heat value below mean? REACTOR TYPE: ISOTHERMAL REACTOR. POWER: M*KCAL/HR – 71.1884. TOTAL REACTION HEAT AT 25.00°C: M*KCAL/HR – 81.7733
A negative heat value indicates heat release; the synthesis of methanol is an exothermic reaction, so it naturally has a negative value. . . . The value below represents the heat of reaction at 25 degrees Celsius. The reason it differs from the value above is that the reaction temperature you specified is likely different from the temperature of the feed material, which results in some of the heat of reaction being consumed
Oh, thanks to the person above; I’m finally getting a reply. What do you mean by the 25-degree reaction heat you mentioned below? Some of the reaction heat has been consumed – how much exactly? You are right; the reaction temperature and the feed temperature are indeed different. Can we talk in detail on QQ? 465960721
Generally, the calculation of reaction heat is based on the standard enthalpies of formation of various substances at 298.15 K, which corresponds to 25 degrees Celsius. Therefore, the standard reaction heat value given also represents the heat change at 25 degrees Celsius. The difference between this value and the actual amount of heat released is what is used to heat the material. Since an isothermal reactor is used, the amount of heat required to heat the material is the heat consumed in raising its temperature from the feed temperature to the reaction temperature