Calculation of the vaporization volume of storage tanks
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There is a very simple way to calculate the vaporization rate of storage tanks: G = (5.38 + 4.1u) * Pv * F * M^0.5 / 133.32. We would appreciate your opinions – what does the vaporization area F refer to? In what situations can this formula be used, and is it applicable to tanks with internal floating roofs or those with fixed roofs? In the case of fixed-roof containers, if the evaporation area is calculated based on the cross-sectional area, the amount of vaporization will be very high, regardless of the substance in question. Fixed-roof containers are equipped with a vent valve; therefore, the loss caused by that vent valve should also be taken into account. For internal floating roof or external floating roof storage tanks, internal floating roof tanks have vent holes – should the vaporization area be calculated based on the area of these vent holes? Are there any simple methods for calculating the vaporization rate of floating roof tanks and fixed roof tanks? During the design process of storage tanks, the transition from fixed-roof tanks to the current floating-roof tanks was certainly made only after it was proven that floating-roof tanks offer energy savings; are there any comparative data on this aspect?
Is this question a bit difficult? Everyone is still busy
Volatile loss is not considered for internal floating roof tanks, right? This formula should apply to fixed roofs, but the loss is also greatly influenced by the properties of the material, as well as temperature and area; the calculated value should be low. I’m not sure what kind of material the original poster is using
Should the vaporization area of a fixed roof be its cross-sectional area? I find that the volatility is too high.
I’m also calculating the vaporization volume of the storage tank. Has the original poster resolved it?