Compression ratio of vacuum ejector
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Could everyone please help explain the compression ratio of the ejector? I can simply think of the compression ratio of a vacuum pump as compressing the inhaled gas from 6 to 1, thereby increasing the pressure and expelling it from the system. But how is the compression ratio of the vacuum ejector explained? How is the pressure in the mixing chamber of a vacuum ejector calculated? Please give me some advice. Thank you.
The compression ratio is the ratio of the pressure at the ejector outlet to the pressure of the gas being pumped; it effectively increases the pressure of the gas being pumped, which means that the volume of the gas is compressed.